Maharashtra Board Class 11 Maths Part 2 Chapter 2 Sequences and Series Ex 2.2 Solution

Question 1.
For the following G.P.s, find .
(i) 3, 6, 12, 24, ……..
Solution:

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Solution:

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(iii) 0.7, 0.07, 0.007, …….
Solution:
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(iv) √5, -5, 5√5, -25, …….
Solution:
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Question 2.
For a G.P.

Solution:
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(ii) If = 1023, r = 4, find a.
Solution:
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Question 3.
For a G.P.
(i) If a = 2, r = 3,  = 242, find n.
Solution:
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(ii) For a G.P. sum of the first 3 terms is 125 and the sum of the next 3 terms is 27, find the value of r.
Solution:
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Question 4.
For a G.P.

Solution:

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Solution:
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Question 5.
Find the sum to n terms
(i) 3 + 33 + 333 + 3333 + …..
Solution:

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(ii) 8 + 88 + 888 + 8888 + …..
Solution:
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Question 6.
Find the sum to n terms
(i) 0.4 + 0.44 + 0.444 + …..
Solution:

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(ii) 0.7 + 0.77 + 0.777 + ……
Solution:
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Question 7.
Find the sum to n terms of the sequence
(i) 0.5, 0.05, 0.005, …..
Solution:
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(ii) 0.2, 0.02, 0.002, ……
Solution:
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Question 8.
For a sequence, if  = 2(3n – 1), find the nth term, hence showing that the sequence is a G.P.
Solution:

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Question 9.

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Question 10.

Solution:
Let a and r be the 1st term and common ratio of the G.P. respectively.
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Question 11.
Find

Solution:
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Solution:
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Question 12.
The value of a house appreciates 5% per year. How much is the house worth after 6 years if its current worth is Rs. 15 Lac. [Given: (1.05 = 1.28, (1.05 = 1.34]
Solution:

The value of a house is Rs. 15 Lac.
Appreciation rate = 5% = 5/100 = 0.05
Value of house after 1st year = 15(1 + 0.05) = 15(1.05)
Value of house after 6 years = 15(1.05) (1.05
= 15(1.05
= 15(1.34)
= 20.1 lac.

Question 13.
If one invests Rs. 10,000 in a bank at a rate of interest 8% per annum, how long does it take to double the money by compound interest? [(1.08 = 1.47]
Solution:

Amount invested = Rs. 10000
Interest rate = 8/100 = 0.08
amount after 1st year = 10000(1 + 0.08) = 10000(1.08)
Value of the amount after n years
= 10000(1.08) × (1.08
= 10000(1.08
= 20000
∴ (1.08 = 2
∴ (1.08 = 1.47 …..[Given]
∴ n = 10 years, (approximately)