Maharashtra Board Text books

Chapter 4 Ratio and Proportion Practice Set 4.4

Question 1.
Fill in the blanks of the following.


Solution:
Maharashtra Board Class 9 Maths Solutions Chapter 4 Ratio and Proportion Practice Set 4.4 2

Question 2.
5m – n = 3m + 4n, then find the values of the following expressions.

Solution:

5m – n = 3m + 4n … [Given]
∴ 5m – 3m = 4n + n
∴ 2m = 5n
Maharashtra Board Class 9 Maths Solutions Chapter 4 Ratio and Proportion Practice Set 4.4 4
Maharashtra Board Class 9 Maths Solutions Chapter 4 Ratio and Proportion Practice Set 4.4 5

Question 3.
Solve:

Solution:
Here, no two of a, b and c are equal.
∴ values of (b – c), (c – a) and (a – b) are not zero.
a(y + z) = b(z + x) = c(x + y) … [Given]
Maharashtra Board Class 9 Maths Solutions Chapter 4 Ratio and Proportion Practice Set 4.4 6
Maharashtra Board Class 9 Maths Solutions Chapter 4 Ratio and Proportion Practice Set 4.4 7


Solution:

Maharashtra Board Class 9 Maths Solutions Chapter 4 Ratio and Proportion Practice Set 4.4 8


Solution:

Maharashtra Board Class 9 Maths Solutions Chapter 4 Ratio and Proportion Practice Set 4.4 9


Solution:

Maharashtra Board Class 9 Maths Solutions Chapter 4 Ratio and Proportion Practice Set 4.4 10
Maharashtra Board Class 9 Maths Solutions Chapter 4 Ratio and Proportion Practice Set 4.4 11


Solution:
Maharashtra Board Class 9 Maths Solutions Chapter 4 Ratio and Proportion Practice Set 4.4 12

Question 4.
Solve:

Solution:
Maharashtra Board Class 9 Maths Solutions Chapter 4 Ratio and Proportion Practice Set 4.4 14
Maharashtra Board Class 9 Maths Solutions Chapter 4 Ratio and Proportion Practice Set 4.4 15
∴ 7(4x – 5)3(2x + 3)
∴ 28x – 35 = 6x + 9
∴ 28x – 6x = 9 + 35
∴ 22x = 44
∴ x = 2
∴ x = 2 is the solution of the given equation.

ii. 5y2+40y−125y+10y2−4=y+81+2y
Maharashtra Board Class 9 Maths Solutions Chapter 4 Ratio and Proportion Practice Set 4.4 16
Maharashtra Board Class 9 Maths Solutions Chapter 4 Ratio and Proportion Practice Set 4.4 17
∴ y + 8 = 3(1 + 2y)
∴ y + 8 = 3 + 6y
∴ 8 – 3 = 6y – y
∴ 5 = 5y
∴ y = 1
∴ y = 1 is the solution of the given equation.