I. Solve the following differential equations:
Question 1.
Solution:
Question 2.
Question 3.
Solution:
Question 4.
Substituting these values in (1), we get
Question 5.
Solution:
Question 6.
Solution:
Question 7.
Solution:
Question 8.
Solution:
Question 9.
Solution:
Question 10.
Solution:
Question 11.
x dy + 2y · dx = 0, when x = 2, y = 1
Solution:
∴ x dy + 2y · dx = 0
∴ x dy = -2y dx
Integrating, we get
This is the general solution.
When x = 2, y = 1, we get
4(1) = c
∴ c = 4
Question 13.
Question 14.