I. Solve the following differential equations:
Question 1.
Solution:
Question 2.


Question 3.
Solution:

Question 4.
Substituting these values in (1), we get

Question 5.
Solution:


Question 6.
Solution:


Question 7.
Solution:

Question 8.
Solution:

Question 9.
Solution:

Question 10.
Solution:

Question 11.
x dy + 2y · dx = 0, when x = 2, y = 1
Solution:
∴ x dy + 2y · dx = 0
∴ x dy = -2y dx![]()
Integrating, we get
This is the general solution.
When x = 2, y = 1, we get
4(1) = c
∴ c = 4

Question 13.



Question 14.



