Question 1.
Without expanding, evaluate the following determinants.
Solution:
Question 2.
Solution:
Question 3.
Using properties of determinant, show that
= -2[0(ab – 0) – a(bc – 0) + b(0 – ac)]
= -2(0 – abc – abc)
= -2(-2abc)
= 4abc = R.H.S.
ii.
Question 4.
Solve the following equations.
Question 5.
Solution:
∴ x = 0 or 12 – x = 0
∴ x = 0 or x = 12
Question 6.