Maharashtra Board Text books

Maharashtra Board Class 11 Maths Part 2 Chapter 9 Differentiation Ex 9.2 Solution

(I) Differentiate the following w.r.t. x

Question 1.


Solution:

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Question 2.
y = √x + tan x – x3
Solution:

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Question 3.

Solution:
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Question 4.

Solution:

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Question 5.

Solution:
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Question 6.

Solution:

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(II) Diffrentiate the following w.r.t. x

Question 1.
y = x5 tan x
Solution:
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Question 2.
y = x5 log x
Solution:

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Question 3.
y = (x2 + 2)2 sin x
Solution:
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Question 4.
y = ex log x
Solution:

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Question 5.

Solution:
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Question 6.

Solution:
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(III) Diffrentiate the following w.r.t. x

Question 1.
y = x2√x + x4 log x
Solution:

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Question 2.

Solution:

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Question 3.
y = x4 + x√x cos x – x2 ex
Solution:

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Question 4.
y = (x3 – 2) tan x – x cos x + 7x . x7
Solution:

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Question 5.
y = sin x log x + ex cos x – ex √x
Solution:
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Question 6.
y = ex tan x + cos x log x – √x 5x
Solution:

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(IV) Differentiate the following w.r.t.x.

Question 1.

Solution:

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Question 2.

Solution:

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Question 3.

Solution:
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Question 4.

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Question 5.

Solution:
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Question 6.

Solution:

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(V).

Question 1.
If f(x) is a quadratic polynomial such that f(0) = 3, f'(2) = 2 and f'(3) = 12, then find f(x).
Solution:

Let f(x) = ax2 + bx + c …..(i)
∴ f(0) = a(0)2 + b(0) + c
∴ f(0) = c
But, f(0) = 3 …..(given)
∴ c = 3 …..(ii)
Differentiating (i) w.r.t. x, we get
f'(x) = 2ax + b
∴ f'(2) = 2a(2) + b
∴ f'(2) = 4a + b
But, f'(2) = 2 …..(given)
∴ 4a + b = 2 …..(iii)
Also, f'(3) = 2a(3) + b
∴ f'(3) = 6a + b
But, f'(3) = 12 …..(given)
∴ 6a + b = 12 …..(iv)
equation (iv) – equation (iii), we get
2a = 10
∴ a = 5
Substituting a = 5 in (iii), we get
4(5) + b = 2
∴ b = -18
∴ a = 5, b = -18, c = 3
∴ f(x) = 5x2 – 18x + 3

Check:
If f(0) = 3, f'(2) = 2 and f'(3) = 12, then our answer is correct.
f(x) = 5x2 – 18x + 3 and f'(x) = 10x – 18
f(0) = 5(0)2 – 18(0) + 3 = 3
f'(2) = 10(2) – 18 = 2
f'(3) = 10(3) – 18 = 12
Thus, our answer is correct.

Question 2.

Solution:

f(x) = a sin x – b cos x
Differentiating w.r.t. x, we get
f'(x) = a cos x – b (- sin x)
∴ f'(x) = a cos x + b sin x
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Now, f(x) = a sin x – b cos x
∴ f(x) = (√3 + 1) sin x + (√3 – 1) cos x

VI. Fill in the blanks. (Activity Problems)

Question 1.
y = ex . tan x
Diff. w.r.t. x

Solution:

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Question 2.

diff. w.r.t. x

Solution:

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Question 3.
y = (3x2 + 5) cos x
Diff. w.r.t. x

Solution:

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Question 4.
Differentiate tan x and sec x w.r.t. x using the formulae for differentiation of  and  respectively.
Solution:

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